Question

5. A number is selected at random from the first 50 natural numbers.
What is the probability that it is a multiple of 3 and 4?
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Answer 1

Answer:

105,112, 119,................. 196 these are the number so

a=105

an=196

d=112-105=7

now substitute in the formula an=a+(n-1)d

196=105+(n-1)7

196=105+7n-7

196=98+7n

98=7n

n=98÷7

n=14 now substitute in an formula

sn=n/2[2a+(n-1)d]

sn=7[2×105+13×7]

sn=[210+91]7

sn=2107

mark it as brainliestt pleasee