Question

5 a paramagnetic sample shows a net magnetization of 8 am1 when placed in an external magnetic field of 0.6t at a temperature of 4k. When the same sample is placed in an external magnetic field of 0.2 t at a temperature of 16k, the magnetization will be

Answer 1

The magnetization will be 2/3 Am⁻¹.

We know, that the intensity of magnetisation (I) is proportional to the magnetic induction (B) divided by Temperature in Kelvin (T)

So, I ∝ B/T

Let two magnetic intensities be I₁ and I₂ , temperatures be T₁ and T₂ and magnetic inductions be B₁ and B₂.

Thus, I₂/I₁ = (T₁B₂)/(T₂B₁)  ...(1)

So,  I₁ = 8 Am⁻¹, B₁ = 0.6T, T₁ = 4K, B₂ = 0.2 T and T₂ = 16K

Putting the respective values in eqn. (1), we get:

So, I₂/8 = (0.2*4)/(0.6*16)

⇒ I₂ = 2/3 Am⁻¹

This is the required answer.