Question

5. A particle is executing simple harmonic motion with amplitude A. At a displacement of A/4 from the equilibrium position, the ratio of kinetic and potential energy of the particle will be?
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Answer 1

explanation:

K.E= 1/2

k(A^2-x^2)

P.E= 1/2kx^2

Given :  

P.E/K.E=1/4

(A^2-x^2)/x^2=1/4

=2A/root5

Answer 2

Answer:

a/4 is the potential energy