Physics, asked by Nikhilgautam12, 1 year ago

5.
A particle of charge 1 uC is at rest in a magnetic field B = -2k tesla. Magnetic Lorentz force on the charge
particle with respect to an observer moving with velocity j = -5i ms' will be
(1)
Zem
12
10-5
IN​

Answers

Answered by aristocles
23

Answer:

Magnetic Lorentz force on the charge particle will be

F = 10^{-5}\hat j

Explanation:

As we know that magnetic Lorentz force is given by

F = q(\vec v \times \vec B)

here we know that

\vec v = v_q - v_{observer}

\vec v = 0 - (-5\hat i)

\vec v = 5 \hat i

Now we will have

F = (1\mu C)(5\hat i \times (-2\hat k))

F = (1\times 10^{-6})(10 \hat j)

F = 10^{-5}\hat j

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Topic : Magnetic Lorentz Force

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