Question

5. A particle starts with a velocity of 2 ms- and moves in a
straight line with a retardation of 0.1 ms. The first time at
which the particle is 15m from the starting point is
(2) 10s (b) 205 (c) 305 (d) 40s​

Answer 1

i hope this will help you

Answer 2

The first time at  which the particle is 15 m from the starting point is 10 seconds.

Explanation:

It is given that,

Initial speed of the particle, u = 2 m/s

Retardation of the particle, $a=-0.1\ m/s^2$

Distance, d = 15 m

Let t is the time at  which the particle is 15 m from the starting point is. It can be calculated using second equation of motion as :

$d=ut+\dfrac{1}{2}at^2$

$15=2t+\dfrac{1}{2}(-0.1)t^2$

On solving the above equation,

t = 10 s

So, the first time at  which the particle is 15 m from the starting point is 10 seconds. Hence, this is the required solution.

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Second equation of motion

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