Question

5. A pendulum having an amplitude 'A' is executing SHM as shown in the figure.
How much is the displacement between two extreme position :
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Answer 1

Answer:

${d}^{2} = \sqrt{\cos( \theta)}$

Explanation:

you use the cosine rule

use cosine rule and substitute values

${d}^{2} = {l}^{2} + {l}^{2} - 2(l)(l) \times \cos( \theta)$

${d}^{2} = 2{l}^{2} - 2{l}^{2} \times \cos( \theta)$

${d}^{2} = \sqrt{\cos( \theta)}$