5. A person saves 180 minutes in covering a certain distance, when he increases his speed from 25 kmph to 30 kmph. Find the distance
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distance=speed × time
speed = (30 -25) kmph = 5 ×1000÷(60*60)m/s
time= 180 minutes = 10800 seconds
hene, distance = 5×1000÷(60*60) ×10800
= 15000 m = 15km
speed = (30 -25) kmph = 5 ×1000÷(60*60)m/s
time= 180 minutes = 10800 seconds
hene, distance = 5×1000÷(60*60) ×10800
= 15000 m = 15km
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