Question

5. A person standing between two vertical cliffs produces a sound and hesrs two successive echoes in 3s and 5s.If speed of sound is 330m/s then distance between cliffs is
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Answer 1

Answer:

Distance traveled by the sound from the 1st cliff is calculated with the formula:

Distance traveled = velocity of sound × time taken 

That is, 320×4 =1280 m. 

This is twice the minimum distance between a source of sound (man) and the reflector (1st cliff) as it is reflected sound. 

Distance traveled by the sound from the 2nd cliff is calculated with the formula:

Distance traveled = velocity of sound × time taken

That is, 320×6=1920 m. 

This is twice the minimum distance between a source of sound (man) and the reflector (2nd cliff) as it is reflected sound. 

Hence, the distance between the 2 cliffs is given as: 21280+21920=640+960=1600 m

Answer 2

Answer:

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