Question

5. A person travels a distance of 5 m towards the east, then turn left and travels 12 m towards the north,
a) What is the total distance travelled by the person?
b) What is his displacement?​

Answer 1

Answer:

Total distance travelled=17m

Total displacement=13m

Explanation:

Total distance travelled =Sum of the total distance travelled by the person=12+5=17m

Displacement=

$\sqrt{12 \times 12 + 5 \times 5}$

By Pythagoras Theorem

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Answer 2

Answer:

The total distance travelled by the person = 17m

The displacement of person = 13m

Explanation:

Consider that initially person was standing at point O. Then he travelled distance OA = 5m in east direction (as shown in the attached figure below).

From point A, he turned left and travelled distance AB = 12m  towards north direction, By constructing the path we get a right angle triangle OAB.

• The total distance travelled by the person from initial point 'O' and final point 'B' = OA + AB = 5m + 12m = 17m
• The displacement is the shortest distance between  from initial point 'O' and final point 'B which is equal to OB.

We can find OB, by using Pythagoras theorem on ΔOAB,

OB² = OA² + AB²

OB²  = (5)² + (12)²  

$OB=\sqrt{25+ 144}$

$OB=\sqrt{169}$

$OB=13m$

Therefore, his displacement will be equal to 13m.