Question

5. A photograph of a bacteria enlarged 50,000 times
attains a length of 5 cm as shown in the diagram.
What is the actual length of the bacteria? If the
photograph is enlarged 20,000 times only, what
would be its enlarged length?​

Answer 1

Given

The length of bacteria is 5 cm if the photograph is enlarged 50,000 times.

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To Find

The length of bacteria if the photograph is enlarged 20,000 times.

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Solution

Let the original length of the bacteria be ⇒ x cm

Since the bacteria is enlarged 50,000 times to 5 cm we will solve this equation ⇒ 50000 × x = 5

Let's solve your equation step-by-step

50000 × x = 5

Step 1: Divide 50000 from both sides of the equation.

⇒ 50000 × x ÷ 50000 = 5 ÷ 50000

⇒ x = 0.0001

⇒ x =  $\dfrac{1}{10000}$

⇒ x = 1 × 10⁻⁴

∴ The original breadth of the given bacteria is 1 × 10⁻⁴ cm.

Now, as given in question we need to find the length of the bacteria if it is enlarged 20,000 times.

To find the length of that we will multiply the original value to 20,000.

⇒ (1 × 10⁻⁴) × 20000

⇒ 0.0001 × 20000

⇒ 2 cm

∴ The length of the bacteria if enlarged 20,000 times would be 2 cm.

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Answer 2

Answer:

Actual Length of the bacteria = 5/50000cm

= 10 to the power -4 cm

When the photograph of a bacteria enlarged 50,000 times attains a length = 5 cm

When the photograph of a bacteria enlarged 20,000 times attains a length = =5/50000×20000cm

= 2cm