Question

5. A photograph of a bacteria enlarged 50,000 times
attains a length of 5 cm as shown in the diagram.
What is the actual length of the bacteria? If the
photograph is enlarged 20,000 times only, what
would be its enlarged length?​

Answer 1

Explanation:

Let the actual length of bacteria be x cm and the enlarged length of bacteria be y cm if the photograph is enlarged for 20,000 times.

The given information in the form of a table is as follows.

The number of times the photograph of bacteria was enlarged and the length of bacteria are in direct proportion.

Therefore, we obtain

$\frac{5}{50000}=\frac{x}{1}$

50000

5 = 1x

$\Rightarrow x=\frac{1}{10000}=_{10}-4$⇒x=

10000

Hence, the actual length of bacteria is _{10}-4

10 −4 cm.

Let the length of bacteria when the photograph of bacteria is enlarged 20,000 times be y.

$\frac{5}{50000}=\frac{y}{20000}$

50000 5 = 20000y

$y=\frac{20000\times5}{50000}$=2y=

50000 20000×5 =2

Hence, the enlarged length of bacteria is 2 cm.