5. A physical quantity P is described by the relation P=a? b c d. It the relative errors in the
measurement of a, b, c and d respectively, are 2%, 1%, 3% and 5%, then the relative error in P will be
[JEE Main 17]
(A) 25%
(B) 12%
(C) 8%
(D) 32%
Answers
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ANSWER
P=a
1/2
.b
2
.c
3
.d
−4
Taking log on both sides
logP=
2
1
loga+2logb+3logc−4logd
Now differentiating on both sides
P
dP
=
2a
da
+2
b
db
+3
c
dc
−4
d
d(d)
or
P
ΔP
=
2a
Δa
±2
b
Δb
±3
c
Δc
±4
d
Δd
Now, given,
a
Δa
×100=2,
⇒
b
Δb
×100=1,
⇒
c
Δc
×100=3,
⇒
d
Δd
×100=5,
⇒
P
ΔP
×100=
2
2
±2×1±3×3±4×5
⇒
P
ΔP
×100=32%
pls make my answer brainliest ...
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