Question

5) A plane has a take off speed of 300 m/s. What is the acceleration in m/s2 of the plane if the
plane started from rest and took 45 seconds to take off?​

Answer 1

Answer:

300/45=20/9=2.222m/s2

Explanation:

final velocity=300m/s=v

initial velocity=0=u

time=45sec=t

a=v-u/t

a=300-0/45

a=300/45

a=2.222m/s2