Question

5.
A ray of light is incident in medium 1 on a surface that separates medium 1 from medium 2. Let v, and v2
represent the velocity of light in medium 1 and medium 2 respectively. Also let na and n, represent the
refractive indes of medium 1 with respect to medium 2 and refractive index of medium 2 with respect to
medium 1, respectively. Ifiandr denote the angle of incidence and angle of refraction, then
A sin i÷ sin r = n21 =v1÷v2
B sin i÷ sin r = n21 =v2÷v1
C sin i÷ sin r = n12 =v1÷v2
D sin i÷ sin r = n12 =v2÷v1
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Answer 1

Answer:

If v1 and v2 is velocity of light in medium 1 and medium 2 respective.

If v1 and v2 is velocity of light in medium 1 and medium 2 respective. Then n12, the refractive index of medium 1 with respect to medium 2 is given by :

If v1 and v2 is velocity of light in medium 1 and medium 2 respective. Then n12, the refractive index of medium 1 with respect to medium 2 is given by :n12=v1v2=n211 

If v1 and v2 is velocity of light in medium 1 and medium 2 respective. Then n12, the refractive index of medium 1 with respect to medium 2 is given by :n12=v1v2=n211 Now, according to Snell's law when light is incident on medium 1 with angle i and refracts to medium 2 with angle r then relation between them is given by: 

If v1 and v2 is velocity of light in medium 1 and medium 2 respective. Then n12, the refractive index of medium 1 with respect to medium 2 is given by :n12=v1v2=n211 Now, according to Snell's law when light is incident on medium 1 with angle i and refracts to medium 2 with angle r then relation between them is given by: sin rsin i=n1n2=v2v1=n21

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