5. A rectangle has length 18 cm and breadth 8 cm. If its length is changed by
![\frac{2}{3} \frac{2}{3}](https://tex.z-dn.net/?f=+%5Cfrac%7B2%7D%7B3%7D+)
times and breadth by times, then what is the change on its area?
![\frac{3}{2} \frac{3}{2}](https://tex.z-dn.net/?f=+%5Cfrac%7B3%7D%7B2%7D+)
Will the area remain same or change (explain it)
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Answer:
No change in the area ; it will remain same.
Step-by-step explanation:
Area of the rectangle = length × breadth = 18 × 8 = 144 cm^2
New length = 2/3 × 18 = 12 cm
New breadth = 3/2 × 8 = 12 cm
So, New Area = New length × New breadth = 12 × 12 = 144 cm^2
Hence, the area will remain same. It will not change.
Hope it helps u !!!!!!!
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