Question

5. A rectangular bahay-kubo with the dimension of 11m more than its width built
in a rectangular backyard. The area of the bahay kubo is 85m².​

Answer 1

Answer:

Step-by-step explanation:

lets here,

Let's assume that the width = x

therefore the other one (length) =  (x + 11)

Now we know that,

Area of rectangle (bahay kubo) = 85 m².

Area of rectangle = length X width

Area of rectangle = (x) X  (x + 11)

$x^2 + 11x = 85$

$x^2 + 11x -85 = 0$

Now here by using the quadratic equation formula we get,

x = $\frac{-b+-\sqrt{b^2 -4ac} }{2a}$

x = $\frac{-11 +-\sqrt{11^{2}-4 X 1X(-85_) } }{2}$

after solving we get,

x = 16.23 m

Now the other one (length) =  (x + 11) = 11 + 16.23 = 27.23

the width = x = 16.23 m

#SPJ2

Click the below link to know more:

https://brainly.in/question/28136612

https://brainly.in/question/49357527