5. A rope is 22 m long, two pieces of lengthe5 1/5m and 3 2/10m are cut off. What
is the length of the remaining rope
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Length of remaining rope
=11−(523+3103)
=11−(513+1033)
=11−(1026+33)
=11−1059
=10110−59
=1051
=5101
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