5. A sample of dolomite contained 45% of CaCO3,
40% of MgCO3 and 15% clay. Calculate the mass
of sulphuric acid of 30% strength required to react
completely with 10 g of the sample.
Answers
Answer:
30 grams mass of sulphuric acid of 30% strength required to react completely with 10 g of the sample.
Explanation:
Given data:
A sample of dolomite contained 45% of CaCO3, 40% of MgCO3 and 15% clay.
To find:
mass of sulphuric acid of 30% strength required to reactcompletely with 10 g of the sample.
Solution:
The reaction involved in the process is as follows
CaCO3 + MgCO3 + 2H2SO4 ==> CaSO4 + MgSO4 +2 H2O + 2CO2
mass of CaCO3 = 45% of 10 grams of dolomite
=(45/100)*10
= 4.5 grams
Mass of MgCO3 = 40 % of 10 grams of dolomite
=(40/100)*10
= 4 grams
Now,
Total mass = 1- 4.5+ 4
= 1.5grams
Therefore, 10 grams sample of dolomite will contain
4.5 + 4 = 8.5 g dolomite
It is giving 184 (mass)
grams of dolomite reacts with 2 moles 196 g of H2SO4
8.5 g of dolomite reacts with x grams of H2SO4
Using cross multiplication
Let x g sulphuric acid is needed to react with the sample.
Then,
100 x 9 = 30 x x
x= 900/30
= 30 g
Hence,
30 grams mass of sulphuric acid of 30% strength required to react completely with 10 g of the sample.