Question

5. A ship moving with a constant acceleration of 36 km/h in a fixed direction speeds up from 18 km/h to 36 km/h. Find
the distance traversed by the ship in this period.
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Answer 1

Answer:

5 km is answer.

Explanation:

Given,

Acceleration, a=36km/h2

Initial velocity, u=12km/h

Final velocity, v=18km/h

Using the equation of motion as:

v2−u2=2as

Where, s is distance traversed by ship.

(18)2−(12)2=2(36)s

324−144=36s

s=5km

Distance traversed by ship is 5 Km.

Answer 2

Answer:

v²-u²=2as

v= 18

u= 12

A= 36

18²-12²=2×36×s

324-144= 72×s

180=72s

180÷72=s

s=2.5

Explanation:

v²-u²=2as

v= 18

u= 12

A= 36

18²-12²=2×36×s

324-144= 72×s

180=72s

180÷72=s

s=2.5