5. A shopkeeper purchased a pressure cooker for 1800 and marked it 75% above the cost price. If the discount given by the shopkeeper is 10%. find(i) the marked price,(ii) the selling price, (iii) profit or loss percentage.
Answers
Step-by-step explanation:
given,
CP= 1800
MP is 75% above
i) MP= 1800+1800*75/100
= 3150ans.
d%= 10%
ii) SP= MP- MP of d%
=3150-3150*10/100
=2835ans.
now,
profit (P)= SP - CP
=2835-1800
=1035
p%=P/CP*100
=1035/1800*100
=•••••••••••••
Answer:
Your Answer will be (i) ₹3150 (ii) ₹2835 (iii) 115/2% or 57 1/2 % Gain
Step-by-step explanation:
{Note:- The 'x' denotes multiplication}
(i) CP of cooker = ₹1800
MP if 75% above the CP
Hence MP =
1800 + 75/100 x 1800
1800 + 135000/100
1800 + 1350 (After cutting of zeros)
MP = ₹3150 Ans
(ii) SP = (1-D%) of MP
= (1 - 10/100) x 3150
= 90/100 x 3150 (After doing 100-10/100 x 3150)
SP = ₹2835 Ans
(iii) SP = ₹2835
CP = ₹1800
As, SP>CP
Profit = SP - CP
= ₹2835 - ₹1800
= ₹1035
Profit% = (Profit/CP) x 100
= 1035/1800 x 100
= 115/2% or 57 1/2 % Gain Ans
Hence your Answer is
(i) ₹3150 (ii) ₹2835 (iii) 115/2% or 57 1/2 % Gain