Question

5. A solid cylinder of mass 20kg rotates about its axis with angular speed 100s. The
the cylinder is 0.25m. What is the kinetic energy associated with rotation of the
What is the magnitude of the angular momentum of the cylinder about its axis?​

Answer 1

Hey there!

• Moment of Inertia of (I) of a solid cylinder is given as : $\frac{MR^2}{2}$  

        =  $\frac{ 20 (0.25)^2 }{2}$

        $= 0.625 kgm^2$

• Kinetic energy is given as :  $\frac{1}{2} I w ^2$

        =  $\frac{1}{2} * 0.625 * (100)^2$

        = $3125 joules$  

• Angular momentum is  given by : $Iw$  

         =  $0.625 * 100$

         = 62.5 Js

Hope it helps!

Answer 2

Answer:

please refer the attachment

Explanation:

hopes it helps you