Question

5. A spherical drop of capacitance 1 F is broken
into eight drops of equal radius. Then, the
capacitance of each small drop is
1)1/2uF
2) 1/4uFUF
4) 8uF
3) 1/8 uF​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

Correct option is 1/2 μF.

Potential of a charged sphere is given by the formula

V= kQ/R

Hence, by Q=CV,

C=Q/V = R/K

As per given information, R/k =1μF

After splitting,

8( 4/3 πr^3 )= 4/3 πR^3

r= R/2

Thus, capacitance of each small drop is V= r/k

= 1/2 /kR

= 1/2 μF

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