Question

5. A square plate of side 10 m is placed horizontally 1 m
below the surface of water. The atmospheric pressure
is 1-013 x 105 N m-2. Calculate the total thrust on the
plate.
(Density of water p = 103 kg m-3, g = 9.8 m s-2)

Pls help me to solve ​

Answer 1

Answer:

1.1*10^7N

Explanation:

pressure=1.013*10^5+10^3*9.8*1

P=111150N/m^2

F(thrust) =P*Area

=1.1*10^5*100

=1.1*10^7N

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Answer 2

please mark me brilliant