Question

5
A stone dropped from the top of tower travels 5 th of the height of tower during
the last second of fall. Height of the tower is : (take g = 10 m/s) :-
(1) 52 m
(2) 36 m
(3) 45 m
(4) 78 m​

Answer 1

Answer:

Trying to copy for exam

Answer 2

displacement of the first stone when second is dropped = 5m ,thus time

difference in dropping of the stones is t=

$\frac{2h}{g} = 1 \\ h = \frac{1}{2} g {2}^{2} \\ =\frac{1}{2} (t - 1)^{2} + 25 \\ 2 = 3s \\ thus, \: h = 45m$

45m is the correct answer....