Question

5. A stone is thrown vertically up word from the top of a tower with a velocity of 5ms-1.
It reaches the ground after 8 s. Find the height of the tower.
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Answer 1

Answer:

here is your answer mate !!

Explanation:

Given, initial velocity, u=5ms  −1

 Final velocity, v=0

Since, u is upward & a is downward, it is a retarded motion.  

∴a=−10ms  −2

 

Height attained by stone, s=?

Time take to attain height, t=?

(i) Using the relation, v  2  −u  2

=2as, we have

s=v  2  −u  

2  /2a =(0)  

2  −(5)  

2  /2×(−10)=1.25m

(ii) Using the relation, v=u+at

0=5+(−10)t or

t=5/10=0.5s