Question

5. A stone is thrown vertically upwards with a velocity of 20 m/s, then the time taken by it
to reach the maximum height is ſtake g - 10 m/s)
​

Answer 1

Answer:

Initial Velocity u=40

Fianl velocity v=0

Height, s=?

By third equation of motion

v

2

−u

2

=2gs

0−40

2

=−2×10×s

s=

20

160

⇒s=80m/s

Toatl distance travelled by stone = upward distance + downwars distance =2×s=160m

Total Diaplacement =0, Since the initial and final point is same.