Question

5. A stone with mass 0.8 kg is attached to one end
of a string 0.9 m long. The string will break if
its tension exceeds 600N. The stone is whirled
in a horizontal circle, the other end of the string
remains fixed. Find the maximum speed, the
stone can attain without breaking the string.plz do step wise​

Answer 1

Answer:

Hey Mate

maximum speed (vmax)=25.98/m/s

Explanation:

Given,

Mass of stone (m)=0.8kg

Length of string (r)=0.9m

Maximum tension (Tmax)=600N

Maximum speed (vmax)=?

For maximum speed at which the string will not break,

Tmax=mv2maxr

v2max=Tmaxrm=600∗0.90.8=675

⇒ v=25.98m/s

∴ The maximum speed (vmax)=25.98/m/s

Hope this will help you

Please mark me Brainlist