Question

5. A straight wire 1 m long carries a current of 10 A at
right angles to a uniform magnetic field of 1 Wb m
Find the mechanical force on the wire and the
power required to move it at 15 ms in a plane at
right angles to the field. ​

Answer 1

Answer:

Given: l=1m, current=10A,B=1 Wb/m^2,theta =90 degree,v=15m/s

We know, F=ilbsintheta

F=10×1×1×1=10N

Now, p=Fv=10×15=150W

Thank

Answer 2

Answer:

150W

Explanation:

V=15ms^-1, l=1m, I=10A, Theta=90°

F= BIl=10

p=FV

p= 10×15

p=150W