Question

5. A submarine receives waves of velocity 320m/s after time interval of 25 seconds,
the distance of the object.
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Answer 1

Answer:

8000m

Step-by-step explanation:

Wave Velocity ( v ) = 320 m/s

Time Interval ( t ) = 25 seconds

Let the distance be d m

ATP,

v = $\frac{d}{t}$

320 = $\frac{d}{25\\}$

d = 8000