5. (a) The mean of 16 variates is 8. If each variate is increased by 2 then find the mean of the new
variates.
(b) The mean of 5 numbers is 18. If a number is omitted then the mean of the remaining 4 number
becomes 16. Find the omitted number.
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Answers
the answer of (a) is 10 & of (b) is 26
Step-by-step explanation:
In first case i.e for (a)
first up all, there are 16 varieties
if consider those 16 varieties as,
a+b+c+d.......+ p (16 varieties)
and divided it by 16 (by the mean formula)
so we will get 8 (given)
if we considered the sum of all varieties as 'x'
then, x/16 = 8 (mean formula)
then we get x = 128
now by given condition,
all varieties are increase by 2,
then we've to add 2 in all varieties,
i.e a+2 + b+2 + c+2 ....... p+2
and we already find the sum of all verities
I e 'x' = 128
then now we have to do just add 32 in 128 ( 2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2=32)
we get,
128+32= 160 & divided it by 16 (by mean formula)
so we will get,
160/16 = 10
so the answer of (a) is 10
In second case i.e (b)
the mean of 5 numbers is 18
by the mean formula,
if we considered those 5 verities as,
a+b+c+d+e = 'y'
and divided it by 5 we get 18 (given)
and the value of 'y' is 90 (y/5 = 18 then y= 5×18)
Now one of the number is omitted then,
we have to considered,
a+b+c+d = 'z' (given)
now by mean formula,
z/4=16 then the value of z = 64 (16×4=64)
Now the value of omitted number is,
in first condition we find the sum of 5 verities is 90 & after one no. is omitted we get the sum of 4 varieties is 64.
Then the difference between them is the omitted number,
i.e 90 - 64 = 26
So the value of omitted number is 26.
Hope it will help you...
It was quite big but I think it helps you to understand .
Answer:
a) 10
.
b) 26...
Step-by-step explanation:
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