Question

5. A thin wire bent in the form of an equilateral triangle encloses an area of 16 √13 m². If the same wire is bent to form a circle find the circumference of the circle​

Answer 1

$\huge \tt \green {answer}$

Area of an equilateral ∆ = √3a²/4

Where a=side

Now, given that -

√3a²/4= 121√3

=>a²=121*4

=> a=11*2= 22

Therefore, length of wire = a+a+a=66

Now, this wire is bent into a circle, so circumference of the circle=2πr=66

=>2*(22/7)r=66

=> r=21/2

Now, area of this circle =πr²

=(22/7)*(21/2)²

=693/2

=346.5cm²