5. A train is travelling at a speed of 90 kmh-1. Brakes are applied so as to produce a uniform acceleration of -0.5ms-2. Find how far the train will go before it is brought to rest?
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So,in the question
initial velocity (u) = 90 km/hr=25 m/s
final velocity (v) = 0 m/s
acceleration (a) = -0.5 m/s^2
so,
s
2as=(v^2 - u^2)
(2*(-0.5))s= 0 - 625
s=625 m
initial velocity (u) = 90 km/hr=25 m/s
final velocity (v) = 0 m/s
acceleration (a) = -0.5 m/s^2
so,
s
2as=(v^2 - u^2)
(2*(-0.5))s= 0 - 625
s=625 m
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0
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