Question

5. A train moves with a constant speed of 36
km h-1 in the first 10 minutes, with another cons-
tant speed of 45 km h-' in the next 10 minutes
and then with an acceleration of 5 ms-2 in the
last 10 minutes. Calculate the average speed of
the train for this journey and the total distance
travelled.
​

Answer 1

921km

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Answer 2

Solution :
For first

, speed = 36 km h^(-1) = 10 m//s

S_1 = 10 xx ( 1=0 xx 60) = 6000 m

S-2 = ( 25)/2 xx ( 10 xx 60) ltBrgt


For last

,

,



Distanc etravelled,





Total distance treavelled by train



= 92 1000 m= 921 km

= 10 + 10 + 10



Average speed,





.