Question

5. A train travels at a certain average speed for a distance of 63 km and then travels a distance of 72 km at an average speed of 6 km/h more than its original speed. If it takes 3 hours to complete the total journey, what is its original average speed?.​

Answer 1

Answer:

Step-by-step explanation:

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Let original speed of the train be x km/h.

Then, time taken to travel 63 km = 63/x hours

New speed = (x + 6) km/hr

Time taken to travel 72 km = 72/(x + 6) hours

According to the question,

x2 - 39x - 126 = 0

(x - 42)(x + 3) = 0

x = -3 or x = 42

As the speed cannot be negative, x = 42

Thus, the average speed of the train is 42 km/hr.

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Answer 2

Answer:

Let average speed be x km/hr.

x

63

+

x+6

72

=3

21(x+6)+24x=x

2

+6x

x

2

−39x−126=0

(x−42)(x+3)=0

x=42 km/hr

Step-by-step explanation:

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