Question

5. A tree is broken at a height of 5 m from the ground and its top touched the ground at a distance of 12 m
from the base of the tree. Find the total height of the tree before broken.​

Answer 1

Answer:

Just use pythagoras theorem. √(5² + 12²) = √(25 + 144) = √169 = 13 m

length of the broken part = 13 m

Total height of the tree = 13 + 5 = 18 m

Step-by-step explanation:

Hope it helps. Thank you.

Answer 2

Answer :

Let ABC be the triangle and B be the point where tree is broken at the height 5 m from the ground.

Tree top touches the ground at a distance of AC = 12 m from the base of the tree .

We see that right angle triangle is formed at A.

By Pythagoras Theorem,

BC² = AB² + AC²

BC² = 5² + 12²

BC² = 25 + 144

BC² = 169

BC = √169

BC = 13 m

Then, the original height of the tree = AB + BC

= 5 + 13

= 18 m