Question

5. A truck starts from rest and rolls down a hill with a constant
acceleration. It travels a distance of 400 m in 20 s. Find its
acceleration. Find the force acting on it if its mass is
7 tonnes (Hint: 1 tonne = 1000 kg.)​

Answer 1

Answer:

Initial velocity =u = 0

Distance =s = 400 m

time = t= 20 sec

a = acceleration

Equation of motion :-

s = ut + 1/2at²

400 = 0 + 1/2 × a × 20 × 20

400 = 200 a

a = 2

acceleration = a = 2 m/s²

Force = F

Mass = m = 7000 kg

Acceleration = a = 2 m/s²

F = ma

= 7000 × 2

= 14000 N

Force acting on it is 14000 N.

Hope it helps you.

Answer 2

Answer:14000 N

Explanation:

here are the answer and explanation

I hope it helps

u=0m/s

s=400m

t=20s

we know s=ut+1/2at^2

400=0*20+1/2*a*400

a=2m/s^2

we know the mass of the truck is 7 tonnes=7000kg

F=ma

F=7000*2

F=14000 N