Physics, asked by shekhar9510, 7 months ago

5. A truck starts from rest and rolls down a hill with a constant
acceleration. It travels a distance of 400 m in 20 s. Find its
acceleration. Find the force acting on it if its mass is
7 tonnes (Hint: 1 tonne = 1000 kg.)​

Answers

Answered by nleyungboi
1

given data,

Initial velocity =u=0

Distance =s=400m

time =t=20sec

a= acceleration

We know that,

Equation of motion:-

s=ut+

2

1

at

2

400=0+

2

1

×a×20×20

400=200a

a=2

acceleration =a=2m/s

2

Force =F=?

The force acting on the mass is 7 tonnes(∴1tonne=1000Kg)

Mass m=7×1000=7000Kg

Mass =m=7000kg

Acceleration =a=2m/s

2

F=ma

=7000×2

=14000N

Answered by SiddharthRaj3904
2

Explanation:

Hi...

Since the truck starts from rest, initial velocity(u) = 0 m/s

Displacement(S) = 400m, Time(t) = 20s and Acceleration(a) = ?

So...you can use the second equation of motion to find the acceleration...

S = ut + 1/2at²

Substitute the values and solve...

400 = (0)(20) + 1/2(a)(20)²

400 = 0 + 1/2(a)(400)

400 = 200(a)

Hence, Acceleration(a) = 2m/s²

Now, the formula to find force = Mass × Acceleration

= 7(1000) kg × 2 m/s²

= 14000 N...(N-->Newton)

I hope it helps...

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