Question

5. A truck starts from rest and rolls down a hill with a constant
acceleration. It travels a distance of 400 m in 20 s. Find its
acceleration. Find the force acting on it if its mass is
7 tonnes (Hint: 1 tonne = 1000 kg.)प्लीज आंसर आधे घंटे में दे दीजिए ​

Answer 1

Answer:

Given data:

Mass of stone(m)=7000 kg

Distance(S)=400 meter

Time(t)=20 second

1) We have to find the acceleration of the truck

So from the equation of motion S=ut+

2

1

a×t

2

, whereu=0

S=

2

1

a×t

2

a=

t

2

2×S

=

20×20

2×400

=2

sec

2

m

2) Force acting on truck

So,from newton's 2

nd

law of motion

F

=ma=7000×2=14000N=14kN

Step-by-step explanation:

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Answer 2

Answer: 14000 N

Given parameters

Initial velocity (u) = 0

Distance travelled (s) = 400 m

Time taken (t) = 20 s

1 metric ton = 1000 kg

7 metric ton = 7 × 1000 = 7000 kg

∴ Mass (m) = 7000 kg

We know the formula

s=ut+12at2

Substitute the given parameters in the above equation

400 = 0 + ½ a (20)2

400 = a × 400/2

400 = 200 × a

a = 2 m/s2

Acceleration is equal to 2 m/s2

Force (F) = Mass (m) × Acceleration (a)

Substitute the values of mass and acceleration in the above equation, we get

F = 7000 × 2

F = 14000 n

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