Chemistry, asked by ReoladonIQ, 11 months ago

5. A vessel of capacity 600 cm contains hydrogen
gas at a pressure of 330 cm Hg. What will
be the pressure of hydrogen gas, when the
vessel is connected to another vessel of 300 cm
capacity ?
(Ans. 220 cm of Hg)​

Answers

Answered by Anonymous
49

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V1=600 cm³

P1=330 cm

V2=300+600=900cm³

P2=?

By boyle's law:

V1P1=V2P2

600*330/900

=220 cm of Hg

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Answered by SehajSingh
9

Answer:

220 cm of Hg

Explanation:

Initial volume (V1)= 600 cm^3

Initial pressure(P1)= 330 cm of Hg

Final volume(V2)= 600+300= 900 cm^3  [Both the containers are connected]

According to Boyle's Law,

P1V1=P2V2

=> 330*600= 900*P2

=> P2= 330*600/900

=> P2= 220 cm of Hg

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