5. A vessel of capacity 600 cm contains hydrogen
gas at a pressure of 330 cm Hg. What will
be the pressure of hydrogen gas, when the
vessel is connected to another vessel of 300 cm
capacity ?
(Ans. 220 cm of Hg)
Answers
Answered by
49
V1=600 cm³
P1=330 cm
V2=300+600=900cm³
P2=?
By boyle's law:
V1P1=V2P2
600*330/900
=220 cm of Hg
Answered by
9
Answer:
220 cm of Hg
Explanation:
Initial volume (V1)= 600 cm^3
Initial pressure(P1)= 330 cm of Hg
Final volume(V2)= 600+300= 900 cm^3 [Both the containers are connected]
According to Boyle's Law,
P1V1=P2V2
=> 330*600= 900*P2
=> P2= 330*600/900
=> P2= 220 cm of Hg
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