5 A village had a population of 25,000 three years ago. During the first, second, and third year, the
population increased at the rates of 5%, 6% and 8%, respectively. What is the present population of the
village?
please i need correct answer and with process
Answers
=> Initial Population = 25000
Find the population after 1st year :-
=> Increase = 5% of 25000
=> Increase = 0.05 × 25000 = 1250
=> Population = 25000 + 1250 = 26250
Find the population after 2nd year :-
=> Increase = 6% of 26250
=> Increase = 0.06 × 26250 = 1575
=> Population = 26250 + 1575 = 27825
Find the population after 3rd year ( Present population)
=> Increase = 8% of 27825
=> Increase = 0.08 × 27825 = 2260
=> Population = 27825 + 2260 = 30051
Answer =》The present population is 30051.
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Population 3 years ago = 25000
Population increased at the rate of 5%, 6%, 8%
Now, after an increase in 5% of population,
New population = 25000 + 5% of 25000 = 25000+ 5/100×25000
=26250
After an increase in 6% of the population,
New population= 26250+ 6% of 26250 = 26250+6/100 ×26250 = 27825
After an increase in 8% of the population,
New population = 27825 + 8% of 27825 =
27825+8/100×27825
= 30051
Hence, the present population is 30051