Physics, asked by hitendodwani8517, 1 month ago

5. A weight lifter lifted a load of 400kgf to a height of 2.5 m. Calculate the work done Take
g=10N/kg
(2 points)

Answers

Answered by dateofbirthis12

0

Answer:

work done will be 10000 J

Explanation:

For vertical motion,

W = P.E

W = mgh

W = (400kg)(10N/kg)(2.5m)

W = 10000Nm

W = 10000J

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