5. A wheel of radius 3 m rolls forward half a revolution on
a horizontal ground. The magnitude of the displacement
of the point of the wheel initially in contact with the
ground is:
a. 2pi m
b. root 2 pi m
C.root pi^2+4
d. 3 root pu^2+4
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Answer:
The initial contact point would have moved vertically up by about 2 metres (twice the radius) and horizontal by about 3.14 ( value of Pi X radius) metres.
So the net so the net displacement will be square root of (2 square + 3.14 square). This comes out to be about 3.7 metres
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