5. A window pane is in the shape of regular octagon. Find the cost of polishing the
window pane at Rs 2.50 per m^2.
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Answered by
13
Answer:
area of rectangle in the middle=13×7=91
area of one of the two trapezium s(top and bottom)=1/2×sum of parallel sides×distance between them = (13+7)×5÷2=50m²
area of the two trapezium=100m²
hence total areas 191metre square
total cost = 2.5x191=477.5 rupees
Answered by
0
Answer:
The cost of polishing is 341.25
Step-by-step explanation:
Area of the rectangle = l*b = 13 * 7 = 91m^2
Area of trapezium = 1/2 × 13 * 7 = 91/2
Total area = 91/2 + 91 = ( 91 + 182)/2 = 273/2 m^2
Cost of polishing window = 273/2 × 2.50 = 136.5 × 2.50 = Rs 341.25
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