Question

5. A wire is bent to form a triangle. If the lengths of the sides of the triangle are 3x2 - 4x cm, 2x2 - 4 cm and 6x + 2 cm, find the length of the wire.​

Answer 1

Answer:

${\huge{\textbf{\textsf{{\color{navy}{♡ An}}{\purple{sw}}{\pink{er ♡}}}}}}$

perimeter of ∆ = side + side + side

= (3x²+4x)+(2x²+4)+(6x+2)

= x(3x-4)+2(x²+2)+2(3x+1)

=(x+2+2) [(3x+4)(x²+2)(3x+1)] (ANS)

Answer 2

Answer:

perimeter of ∆ = side + side + side

= (3x²+4x)+(2x²+4)+(6x+2)

= x(3x-4)+2(x²+2)+2(3x+1)

=(x+2+2) [(3x+4)(x²+2)(3x+1)] (ANS)