Question

5. A wire of length 121/2
m is cut into 10 pieces of equal length find. the length of each piece.


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Answer 1

Answer:

6.05

Explanation:

Given :

• Length of the wire is 121/2 which is cut into 10 pieces of equal length.

To Find :

• The length of each piece

Solution :

Length of the wire =>121/2

Same wire is cut into 10 equal pieces

So,

$\rm{Length\ of\ each\ pieces\ =>}\dfrac{121}{2}\div10$

$\Rightarrow \dfrac{121}{2}\times\dfrac{1}{10}$

$\Rightarrow\dfrac{121}{20}$

$\Rightarrow6.05$

Answer 2

$\huge\underline\mathfrak\color{green} Given:-$

• Length of the wire=$\sf{\frac{121}{2}m}$ and it is cut into 10 pieces.

$\huge\underline\mathfrak\color{green}To \: Find:-$

• The length of each piece.

$\huge\underline\mathfrak\color{green} Solution:-$

Length of the wire = $\sf{ \frac{121}{2} \: m}$

It is cut into ten pieces.

$\sf{= \frac{121}{2} \div 10}$

$\sf{ = \frac{121}{2} \times \frac{1}{10} }$

$\sf{ = \cancel\frac{121}{20} }$

$\sf{ = 60.5}$

$\sf{Hence, \: the \: length \: of \: each \: pieces \: of \: the \: wire \: is 60.5 }$