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AABC is isosceles with AB = AC, if ZA = 80°.
What is the measure of ZB?
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Question:
ΔABC is isosceles with AB = AC. If ∠A = 80°. What is the measure of ∠B?
Solution:
ATQ; AB = AC
Here, the angle opposite to AB is ∠ABC and the angle opposite to AC is ∠ABC. And, AB = AC.
We know that angles to opposite equal sides are also equal.
∴ ∠ABC = ∠ACB
According to ASP of a triangle;
⇒ ∠ABC + ∠BCA + ∠CAB = 180°
⇒ ∠n + ∠n + 80° = 180°
⇒ 2∠n = 180° - 80°
⇒ 2∠n = 100°
⇒ ∠n = 100°/2
⇒ ∠n = 50°
⇔ ∠ABC = ∠ACB = ∠n = 50°.
Therefore the measure of ∠B is 50°.
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