Question

5. AB is a diameter of a circle, centre 0. C is a point on the circumference of
circle, such that angle CAB = 2 x angle CBA. Find angle CBA.


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Answer 1

Step-by-step explanation:

∠ACB=90°  (Angle subtended on semi-circle)

In, △ACB,

∠CAB=180°-(∠ACB+∠CBA)

=180°-(90°+70°)

=20°

Now,

∠DCA+∠ACB+∠BAC+∠DAC=180°   [Sum of opp. anglesof cyclic quadrilateralis supplementary.]

∠DCA+90°+20°+30°=180°

∠ACD=180°-40°

Answer 2

Answer:

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Step-by-step explanation: