Question

5. ABC is a triangle and PQ is a straight line meeting AB in P and AC in Q. IfAP=1 cm. and
BP = 3cm., AQ = 1.5 cm., CQ = 4.5 cm.
the
1
Prove that (area of AAPQ) =
(area of AABC).
Gi
16​

Answer 1

Step-by-step explanation:

In ∆APQ and ∆ABC

angle A = angle A

AB=AP + PB = 1+3 = 4cm

AP÷AB= AQ÷AC

∆APQ = ∆ABC

area ( ∆ APQ)÷ area (∆ABC) = 1÷16

area ( ∆ APQ) = 1÷16 × area ( ∆ ABC)