5. ΔABC is right angled at A and AL ┴ BC. Prove that ∠BAL = ∠ACD.
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In △ABL,
∠BAL+∠ALB+∠B=180
o
∠BAL+90
o
+∠B=180
o
∠BAL=90
o
−∠B ......(1)
In △ABC,
∠A+∠B+∠C=180
o
∠B+∠C=90
o
∠C=90
o
−∠B
∠ACB=90
o
−∠B .......(2)
From 1 and 2, we get,
∠BAL=∠ACB
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