Math, asked by DEBANGSH15, 4 months ago

5. ABCD IS A SQUARE WHOSE SIDE IS 12m. PQRS IS A RECTANGLE
WHOSE LENGTH IN 12.5m AND BREADTH IS 10m. WHICH HAS THE
GREATER AREA AND BY HOW MUCH
(a)PQRS: 9m2 (b) ABCD: 19m2 (C) ABCD: 10m2 (d) NONE​

Answers

Answered by Anonymous
1

Answer:

b) ABCD: 19 m²

Step-by-step explanation:

Area of square = 12 m × 12 m = 144 m²

Area of rectangle = 12.5 m × 10 m = 125 m²

∵ 144 m² > 125 m²,

Area of square is greater.

144 m² - 125 m² = 19 m²

Hence, Area of ABCD is greater than 19 m².

Answered by leharbafna2030
1

Answer:

(b) ABCD: 19m2

Step-by-step explanation:

Formula to find Area of a Square: side x side

=12x12= 144 sq. m

Formula to find Area of a Rectangle:

length x breadth

= 12.5x10= 125 sq. m

Difference between Area of Square and a Rectangle: 144-125= 19

Ans. Area of ABCD Square is greater than PQRS Rectangle by 19m2 does option (b) is correct.

EXPLANATION BY LEHAR BAFNA.

Similar questions